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15s^2-22s+8=0
a = 15; b = -22; c = +8;
Δ = b2-4ac
Δ = -222-4·15·8
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2}{2*15}=\frac{20}{30} =2/3 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2}{2*15}=\frac{24}{30} =4/5 $
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